Question
How many students appeared in exam X or in exam
Z? Study the following information carefully and answer the given questions: There are 1000 students in a college. Out of 1000 students some appeared in exams ‘X’, ‘Y’ and ‘Z’ while some not. Number of student not appeared in any exam is equal to number of students appeared in exam ‘Z’ only. Number of students appeared in exam ‘Y’ is 360. Ratio of number of students appeared in exam ‘X’ and ‘Y’ only to number of students appeared in exam ‘Y’ and ‘Z’ only is 2:3. Number of student appeared in exam ‘X’ and ‘Z’ both is half of number of students appeared in only exam ‘Z’. Number of students appeared in exam ‘X’ only is 50% more than number of students appeared in ‘Y’ only. Number of students appeared in all the three exam is 4% of the total number of students in the college. Number of students appeared in ‘Y’ exam only is same as number of students appeared in ‘Y’ and ‘Z’ only.Solution
Total students = 1000 Let, students appear in exam Z only = a Total students appeared in exam Y = 360 Ratio of number of students appeared in exam X and Y only to students appeared in exam Y and Z only = 2:3 Students appeared in exam X and Z both = a/2 Number of students appeared in all three exams = (4/100) × 1000 = 40 Number of students appeared in Y exam only = No. of students appeared in Y and Z only = 3x Number of students appeared in exam X and Y only = (2/3) × 3x = 2x Now, 2x + 3x + 3x + 40 = 360 ⇒ x = 40 And, 12.5x + a + a/2 + a = 1000 => 5a/2 = 500 ⇒ a = 200 
Students appeared in exam X or in exam Z = 180 + 60 + 40 + 80 + 200 + 120 = 680
Five years ago, the average age of a family of four members was 25 years. Six years hence, the ratio of their ages will be 9:7:5:3. Find the a...
The present ages of A and B are in the ratio 7 : 5. After 6 years, the ratio of their ages will be 4 : 3. Find A's present age.
My grandfather’s age was seven times older to me 14 years ago. He would be two times of my age seven years from now. Seven years ago, what was the...
The current average age of students in a class is 24 years. What will the average age of the students be in 6 years?
Present age of ‘A’ is 25% more than that of ‘B’. If 9 years hence from now, ‘B’ will be 6 years younger than ‘A’, then find the sum of p...
6 years from now, the ratio of ages of Amit and Sumit will be 4:5, respectively. The sum of their present ages is 114 years. What is the difference betw...
- Five years from now, the sum of the ages of ‘X’ and ‘Y’ will be 50 years. Ten years ago, ‘X’ was 8 years younger than ‘Y’. What will be the...
Five years from now, K and M together will be 80 years old. If their present ages are in the ratio 4:3, find the difference in their ages.
Five years ago, the ratio of Aman's age to Rahul's age was 6:5. It is also known that Aman's age will be 47 years five years from now. Additionally, R...
Four years ago, the ages of the father and his son were in the ratio 7:2. Four years hence, the ages of the father and his son will be in the ratio 9:4....
Relevant for Exams:
