Question
Average number of girls in all three school together
is:Solution
Let number of girls in School βAβ is βxβ. Number of boys in School βCβ = 1.20 Γ x = 1.2x Total number of students in School βCβ = 1.2x/0.6x = 2x Number of boys in School βBβ = 0.8x + 40 Number of girls in School βBβ = 0.8x + 40 β 120 = 0.8x β 80 Total number of students in School βBβ = 0.8x + 40 + 0.8x β 80 = 1.6x β 40 So, 1.6x β 40 + 2x = 840/0.6 = 1400 Or, 3.6x = 1440 Or, x = 400 Number of girls in School βAβ = 400 Total number of students in School βAβ = 840 + 400 = 1240 Number of boys in School βCβ = 1.2x = 1.2 Γ 400 = 480 Total number of students in School βCβ = 2x = 2 Γ 400 = 800 Number of girls in School βCβ = 0.8 Γ 400 = 320 Let number of boys in School βBβ = 0.8 Γ 400 + 40 = 360 Number of girls in School βBβ = 0.8 Γ 400 β 80 = 240 Total number of students in School βBβ = 360 + 240 = 600 Desired Average = (400 + 240 + 320)/3 = 320
Consensus ad idem means
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