Question
If (x β 3) is a factor of (x2 + 4qx β
2q), then the value of q is:Solution
(x β 3) is a factor of (x2 + 4qx β 2q) so, x β 3 = 0 => x = 3 Put, x = 3 in x2 + 4qx β 2q and equate to zero. => x2 + 4qx β 2q = 0 => (3)2 + 4 Γ q Γ 3 β 2q = 0 => 9 + 12q β 2q = 0 => 12q β 2q = -9 => q = -9/10
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