Question
Four years ago from now, ratio of ages of two friends
'A' and 'B' was 3:4 respectively. If sum of their present ages is 50 years, then find the present age of 'C' whose present age is 25% less than that of 'B'.Solution
Let the ages of 'A' and 'B', four years ago from now was '3a' and '4a' years respectively.
So, 3a + 4 + 4a + 4 = 50
Or, 7a = 42
Or, 'a' = 6
So, present age of 'B' = 4 x 6 + 4 = 28 years
Therefore, present age of 'C' = (75/100) x 28 = 21 years
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