Question
Present age of βCβ is 20% more than that of βDβ.
3 years ago, βCβ was 1.4 times as old as βDβ. Find the present age of βDβ.Solution
Let the present age of βDβ be βxβ years
Therefore, present age of βCβ = 1.2x years
ATQ;
(1.2x β 3) = 1.4 Γ (x β 3)
Or, 1.2x β 3 = 1.4x β 4.2
Or, 1.2 = 0.2x
Or, x = 6
Therefore, present age of βDβ = 6 years
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