Question
Five years ago, age of P was 15 years less than 1.2 times his present age. The ratio of age of Q, 6 years hence to the age of R, 4 years ago is 3:2. Find the age of Q, if the age of R is 40% less than the age of P.
Solution
Let the present age of P, Q and R be ‘p’, ‘q’ and ‘r’ years respectively. p – 5 = 1.2 × p – 15 0.2 × p = 10 p = 10/0.2 p = 50 years So, age of r = 50 × 0.6 = 30 years Also, (q + 6)/(r – 4) = 3/2 q + 6 = (3/2) × 26 q = 39 – 6 = 33 years
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