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      Question

      6 years ago from now, the average age of β€˜P’ and

      β€˜Q’ was 28 years. The ratio of present age of β€˜P’ and β€˜R’ is 4:5, respectively. If β€˜R’ is 5 years younger than β€˜Q’, then find the age of β€˜Q’ 6 years hence from now.
      A 55 years Correct Answer Incorrect Answer
      B 52 years Correct Answer Incorrect Answer
      C 43 years Correct Answer Incorrect Answer
      D 46 years Correct Answer Incorrect Answer
      E 49 years Correct Answer Incorrect Answer

      Solution

      Let the present age of β€˜P’ and β€˜R’ be 4x years and 5x years respectively. So, the present age of β€˜Q’ = (5x + 5) years Sum of the ages of β€˜P’ and β€˜Q’ 6 years ago from now = 28 X 2 = 56 years Sum of the present age of β€˜P’ and β€˜Q’ = 56 + 12 = 68 years ATQ, (4x + 5x + 5) = 68 Or, 9x = 63 So, β€˜x’ = 7 So, the present age of β€˜Q’ = 5 X 7 + 5 = 40 years Therefore, required age = 40 + 6 = 46 years

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