Question
If present age of ‘A’ is four times the age of
‘B’, 3 years ago from now and sum of their ages 5 years hence from now will be 68 years, then find the present age of ‘B’.Solution
Solution Let present age of ‘B’ = ‘x’ years So, present age of ‘A’ = 4 × (x – 3) years ATQ, (x + 5) + {4(x – 3) + 5} = 68 Or, 5x – 2 = 68 Or, 5x = 70 Or, x = 14 So, present age of ‘B’ = 14 years
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