Question
If present age of ‘A’ is four times the age of
‘B’, 3 years ago from now and sum of their ages 5 years hence from now will be 68 years, then find the present age of ‘B’.Solution
Solution Let present age of ‘B’ = ‘x’ years So, present age of ‘A’ = 4 × (x – 3) years ATQ, (x + 5) + {4(x – 3) + 5} = 68 Or, 5x – 2 = 68 Or, 5x = 70 Or, x = 14 So, present age of ‘B’ = 14 years
If 64x3 - 343y3 = (4x - Ay) X (Bx2 + 49y2 + Cxy), then find the value of 3 X (2A + 6B) - 2C.
If a + b + c = 8, a² + b² + c² = 18 and ab + b c+ ca = 12, then what is the value of a³ + b³ +c³ –3abc?
If
= 4 then 
(a + 7)2 + (b – 2) 2 + (c + 3) 2 = 0, then find the value of 3a - 2b + c.
Two positive numbers differ by 2, and the sum of their reciprocals is 3/4. What is the larger number?
(x + 1)2 + (y – 3) 2 + (z + 5) 2 = 0, then find the value of 2x + 3y - z.
If x + 1/x = 5, then x2 + 1/x2 is:
(x – 6) 2 + (y + 2) 2 + (z – 4) 2 = 0, then find the value of 4x - 3y + z.
22% of ‘x’ is equal to 66% of ‘y’, then find the value of x: y.
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