Question
If present age of βAβ is four times the age of
βBβ, 3 years ago from now and sum of their ages 5 years hence from now will be 68 years, then find the present age of βBβ.Solution
Solution Let present age of βBβ = βxβ years So, present age of βAβ = 4 Γ (x β 3) years ATQ, (x + 5) + {4(x β 3) + 5} = 68 Or, 5x β 2 = 68 Or, 5x = 70 Or, x = 14 So, present age of βBβ = 14 years
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