Start learning 50% faster. Sign in now
The ratio between the present ages of son and daughter is 3:5 respectively.
Let’s assume the present ages of son and daughter are ‘3z‘ and ‘5z‘ respectively.
Five years hence, the age of father is nine years more than double the age of daughter.
So five years hence, the age of daughter = (5z+5)
Five years hence, the age of father = 2(5z+5)+9
= 10z+10+9
= 10z+19
Present age of father = 10z+19-5
= 10z+14
If the present age of father is 64 years
10z+14 = 64
10z = 64-14
10z = 50
z = 5
present age of son = 3z = 3x5 = 15 years
present age of daughter = 5z = 5x5 = 25 years
Twelve years ago, the average age of a family having four members (father, mother, son and daughter) is (y-2) years.
Twelve years ago, the age of father + Twelve years ago, the age of mother + Twelve years ago, the age of son + Twelve years ago, the age of daughter = 4(y-2)
(64-12)+Twelve years ago, the age of mother+(15-12)+(25-12) = 4(y-2)
52+Twelve years ago, the age of mother+3+13 = 4(y-2)
Here the information about two things which are the age of the mother and the value of ‘y’ are unknown. So we cannot determine the age of mother 18 years hence from the given information.
Small reddish brown spot surrounded by water soaked margin with yellow holes appear on soybean pods are the symptoms of:
Acidic soils are found in
Application of super digested compost to acidic calcareous and heavy soils increases the availability of
Match List I with List II IMD uses the aridity index on the basis of (PE-AE)/PE to assess fortnight drought situation over India