Question
The cost price of article A and B is Rs. ‘X’ and Rs.
(X + 750), respectively. Article A is sold at 20% profit while article B is sold at 10% loss. If selling price of article B is Rs. 120 more than that of article A and article B is sold after giving a discount of 20%, then find the marked price of article B.Solution
Selling price of article ‘A’ = x × 120% = Rs. 1.2x Selling price of article ‘B’ = (x + 750) × 90% = Rs. 0.90x + 675 According to the question, 0.90x + 675 – 1.2x = 120 675 – 120 = 0.3x 0.3x = 555 x = 1850 Selling price of article ‘B’ = 0.90 × 1850 + 675 = Rs. 2340 Marked price of the article ‘B’ = 2600/90 × 100 = Rs. 1875
More Profit and loss Questions
125% of 129 ÷ 43 × 28 ÷ 7 = ? ÷ √16
25% of 140 + 2 × 8 = ? + 9 × 5
Solve the following:
523 + 523 x 523 ÷ 523
What will come in the place of question mark (?) in the given expression?
30% of 50% of 1200 = 18/11 × ?
(3984 ÷ 24) x (5862 ÷ 40) = ?
? (1/2) = 236 – 25 × 18/2 + 396 ÷ 22
45% of 360 - 160 + ? = √324
30% of 800 - ?2 = 15
? = (√784 - √361) + 102 - 3√512
Relevant for Exams:
