Question
A loss of 10(1/2)% gets converted into a profit of
11(3/5)% when the selling price is increased by Rs132.60. The cost price (in Rs) of the article is:Solution
Let CP of the article be 100a Now, SP for 1st case = 100a - 100a × 10(1/2)% = 89.5a SP for 2nd case = 100a + 100a × 11(3/5)% = 111.6a According to the question, 111.6a - 89.5a = 132.6 ⇒ 22.1a = 132.6 ⇒ a = 132.6/22.1 ⇒ a = 6 So, cost price = 100 × 6 ⇒ Rs. 600 ∴ The cost price (in Rs.) the article is 600.
Find the next term in the series:
4, 9, 19, 39, 79, ?
221, 100, 0, -81, ?
...√(10198 )× √(7220 )÷ 16.69 + 2010.375= ?
827, 820, 806, 785, 757, ?
7    8     ?     13     17     22    28
...76, 80, 89, 105, ?, 166
{(12√5 + 6√5 )} ×{(10√5 - 5√5 )} - 8² + 6² = ?
-1, 5, 23, 59, ?
12   18   31   51   ?   112
What will come in place of the question mark (?) in the following series?
17, 21, 30, 46, ?, 107
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