Question
Ratio of present age of a brother to that of his sister
is 6:1. After 8 years the ratio will become 2:1. What is the difference (in years) in their present ages?Solution
Let present age of brother and his sister be ‘6x’ years and ‘x’ years, respectively. ATQ; (6x + 8)/(x + 8) = 2/1 Or, 6x + 8 = 2x + 16 Or, 4x = 8 Or, x = 2 Desired difference = 6x – x = 5x = 5 × 2 = 10 years
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