Question
Present age of βAβ is 60% more than that of βBβ.
If 13 years hence from now, βBβ will be 12 years younger than βAβ, then find the sum of present ages of βAβ and βBβ.Solution
Let present age of βBβ be βxβ years Present age of βAβ = x Γ 1.60 = β1.60xβ years ATQ; (x + 13) + 12 = (1.60x + 13) Or, x + 25 = 1.60x + 13 Or, 12 = 0.60x Or, x = 20 So, present age of βBβ = 20 years And, present age of βAβ = 20 + 12 = 32 years Required sum = 20 + 32 = 52 years
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