Question
Four years ago from now, the ages of 'A' and 'B' were
in the ratio 7:5, respectively. Ten years ago from now, the ages of 'A' and 'B' were in the ratio 2:1. Present age of 'A' is how much percent more than that of 'B'?Solution
Let the ages of 'A' and 'B', 10 years ago from now was, '2x' years and 'x' years, respectively. ATQ; {(2x + 6)/(x + 6)} = (7/5) Or, 5 X (2x + 6) = 7 X (x + 6) Or, 10x + 30 = 7x + 42 Or, 3x = 12 So, x = 4 So, present age of 'A' = 2 X 4 + 10 = 18 years And present age of 'B' = 4 + 10 = 14 years So, required percentage = {(18 - 14)/14} X 100 = 28.57%Â
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