Question
The present age of a father is three  times the present age of his son. After 10 years, the father’s age will be twice  the age of his son. What is the present age of the son?
Solution
ATQ, Let son’s present age = x Father’s present age = 3x After 10 years: Son = x + 10 Father = 3x + 10 Given: 3x + 10 = 2(x + 10) 3x + 10 = 2x + 20 3x − 2x = 20 − 10 x = 10 So son’s present age = 10 years.
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