Question
Five years ago, the age of A was 3 times the age of B.
After 7 years, the difference between their ages will be 28 years. Find the present age of A.Solution
ATQ, Let present ages be x and y.
x – 5 = 3(y – 5)
x + 7 – (y + 7) = 28
⇒ x – y = 28
From first:
x – 5 = 3y – 15
x = 3y – 10
Substitute:
3y – 10 – y = 28
2y = 38
y = 19
x = 3(19) – 10 = 47
Present age of A = 47 years
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