Question
The present average age of M and N is 26 years. Twelve
years from now, N's age will be twice what M's age was 4 years ago. What is the ratio of M's present age to N's present age?Solution
ATQ,
Let present age of M and N is βxβ and βyβ years respectively.
So, x + y = 2 Γ 26 = 52β¦β¦β¦β¦β¦β¦..(1)
And, y + 12 = 2 Γ (x β 4)
y + 12 = 2x β 8
2x β y = 20
From equation (1) we get
2x β 52 + x = 20
3x = 72
x = 24
y = 52 β 24 = 28
Desired ratio = 24:28 = 6:7
23% of 8040+ 42% of 545 = ?%of 3000
[192 Γ· 6 Γ 5] Γ· (? + 3) = 20Β
Find the simplified value of the given expression:
1.82Β + 2.42Β + 1.52Β - 1.8 x 2.4 - 2.4 x 1.5 - 1.8 x 1.5
What is the value of β75 + β108?
β4096 + 4/5 of 780 β ? = 296
(25 + 12) x 6 + 34 = ? + 18
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...Solve the following:
523 + 523 x 523 Γ· 523
((12+12+12+12)÷4)/((8+8+8+8+8+8)÷16) = ?
Determine the value of 'p' in the expression.
28 Γ· 22p + 1 = 43Β