Question
The heights (in cm) of 9 basketball players in a
tournament are as follows: 178, 182, 175, 180, 184, 179, 177, 181, 183 Find the median height of the players.Solution
ATQ, Arrange the data in ascending order: 175,177,178,179,180,181,182,183,184 Since the number of observations (n = 9) is odd: Â Here, n = 9, so the median is: Â
The median height is 180 cm.
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?