Question
The average age of A, B, and C is 30 years. 5 years ago,
the sum of the ages of A and B was 12 more than that of C. Find the present age of C.Solution
A+B+C = 20×3=60 5 years before = A+B+C = 90-15 =75 SO, NOW ATQ- (A+B) +C=75 C+12+C = 75 2C =63 C= 31.5 So now the present age of C = 31.5+5=36.5 yearsÂ
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
