Question
The average age of A, B, and C is 30 years. 5 years ago,
the sum of the ages of A and B was 12 more than that of C. Find the present age of C.Solution
A+B+C = 20×3=60 5 years before = A+B+C = 90-15 =75 SO, NOW ATQ- (A+B) +C=75 C+12+C = 75 2C =63 C= 31.5 So now the present age of C = 31.5+5=36.5 yearsÂ
Complete the series by replacing ‘?’
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