Question
8 years ago from now, ratio of ages of βRβ and
βLβ was 3:7, respectively. If βLβ is 8 years elder to βRβ, then what will be the age of βLβ, 6 years hence from now?Solution
8 years ago from now, let ages of βRβ and βLβ be β3xβ years and β7xβ years, respectively. So, 7x β 3x = 8 Or, 4x = 8 Or, x = 2 Present age of βLβ = 7x + 8 = 7Γ 2 + 8 = 23 years Age of βLβ, six years hence from now = 23 + 6 = 28 years
41.66% of 888 + 66.66% of 1176 = ?2Β - 4β 16Β Β
Evaluate: 320 β {18 + 4 Γ (21 β 9)}
Simplify: 72 Γ· 6 Γ 3 β 8 + 4
118 × 6 + 13 + 83 = ?
Simplify the following expression:
Β Β (400 +175) Β² - (400 β 175) Β² / (400 Γ 175)
150% of 850 ÷ 25 – 25 = ?% of (39312 ÷ 1512)
(75 + 0.25 Γ 10) Γ 4 = ?2 - 14
26% of 650 + 15% of 660 – 26% of 450 = ?
115% of 40 + 3 Γ 4 = ? Γ 11 β 8