Question
10 years ago from now, ratio of ages of βRβ and
βLβ was 3:8, respectively. If βLβ is 6 years elder to βRβ, then what will be the age of βLβ, 6 years hence from now?Solution
10 years ago from now, let ages of βRβ and βLβ be β3xβ years and β8xβ years, respectively. So, 8x β 3x = 10 Or, 5x = 10 Or, x = 2 Present age of βLβ = 8x + 6 = 8 Γ 2 + 6 = 22 years Age of βLβ, six years hence from now = 22 + 6 = 28 years
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