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      Question

      10 years ago from now, ratio of ages of β€˜R’ and

      β€˜L’ was 3:8, respectively. If β€˜L’ is 6 years elder to β€˜R’, then what will be the age of β€˜L’, 6 years hence from now?
      A 45 years Correct Answer Incorrect Answer
      B 54 years Correct Answer Incorrect Answer
      C 42 years Correct Answer Incorrect Answer
      D 28 years Correct Answer Incorrect Answer
      E None of these Correct Answer Incorrect Answer

      Solution

      10 years ago from now, let ages of β€˜R’ and β€˜L’ be β€˜3x’ years and β€˜8x’ years, respectively. So, 8x – 3x = 10 Or, 5x = 10 Or, x = 2 Present age of β€˜L’ = 8x + 6 = 8 Γ— 2 + 6 = 22 years Age of β€˜L’, six years hence from now = 22 + 6 = 28 years

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