Question
10 years ago from now, ratio of ages of ‘R’ and
‘L’ was 3:8, respectively. If ‘L’ is 6 years elder to ‘R’, then what will be the age of ‘L’, 6 years hence from now?Solution
10 years ago from now, let ages of ‘R’ and ‘L’ be ‘3x’ years and ‘8x’ years, respectively. So, 8x – 3x = 10 Or, 5x = 10 Or, x = 2 Present age of ‘L’ = 8x + 6 = 8 × 2 + 6 = 22 years Age of ‘L’, six years hence from now = 22 + 6 = 28 years
Let x be the smallest number which when subtracted from 31560 makes the resulting number divisible by 13, 16, 25 and 30. The product of the digits of x ...
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