Question
Present ages of 'A' and 'B' are in the ratio 3:5,
respectively. If B's age, 10 years hence from now will be 5 times of A's age, 22 years ago from now, then find the present age of 'A'.Solution
Let the present ages of 'A' and 'B' be '3x' years and '5x' years, respectively. ATQ; (5x + 10) = 5 x (3x - 22) Or, 5x + 10 = 15x - 110 Or, 10x = 120 x = 12 So, present age of 'A' = 3 x 12 = 36 years
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Only few Letters are Numbers
All Digits are Alphabets
Conclusion:
I. Some L...
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Some children are parents.
All parents are infants.
Some infants are adolescent.
Conclusions:
I. At least...
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Only a few Objectives are Solutions.
Only Subjective are Information.
A few Subjective are Solutions.
Conclusion...
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All ribbons are mat.
Some mats are ropes.
No rope is a thread.
All thread is a needle.
...
Three statements are given followed by two conclusions numbered I & II. Assuming the statements to be true, even if they seem to be at variance with co...
Statement:
No blue is black.
Only a few blacks are Whites.
All Whites are grey.
Conclusion:
I. No blue is Whites.
II. Some grey are not blues
Some tablets are medicines. Some syrups are not capsules. Some tablets are not syrups.
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      All coats are shawls. Â
Conclusions: I. Some sweaters are shawls.
   ...
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All Swabs are Handles.
Only a few Handles are Sticks.
All Sticks are Containers.
Conclusions:
I. Some Swabs are Sticks
II. No Swab is a Stick
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