Question
Present age of ‘A’ is 25% more than that of ‘B’.
If 22 years hence from now, ‘B’ will be 20 years younger than ‘A’, then find the sum of present ages of ‘A’ and ‘B’.Solution
Let present age of ‘B’ be ‘x’ years Present age of ‘A’ = x × 1.25 = ‘1.25x’ years ATQ; (x + 22) + 20 = (1.25x + 22) Or, x + 42 = 1.25x + 22 Or, 20 = 0.25x Or, x = 80 So, present age of ‘B’ = 80 years And, present age of ‘A’ = 80 + 20 = 100 years Required sum = 80 + 100 = 180 years
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