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ATQ: Let the maximum marks of the exam be '100x' Passing marks of the exam = 100x X 0.4 + 20 = 100x X 0.8 - 80 Or, 40x + 20 = 80x - 80 Or, 40x = 100 Or, x = (100/40) = (5/2) Therefore, the maximum marks of the exam = 100x = 100x X (5/2) = 250 Required passing marks = 250 X 0.4 + 20 = 100 + 20 = 120
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