Certain number of students from two schools takes part in an examination. Out of a total of 100 students who participated from ABC school, x% failed in the exam. The number of students in school XYZ are (6x + 10)% more than the number of students in school ABC. 90% of the students who participated from both the school passes the exam. Ther are 217 students from school XYZ who passed the exam. Find out the value of x?
Total number of students in school ABC = 100 So, the number of students from school ABC who failed in the exam = x% of 100 = x So, the number of students from school ABC who passed the exams = 100 – x 
Total number of students from both schoolABC and XYZ = 100 + (110 + 6x) = 210 + 6x 
So, total students who passed the exam from school XYZ is, 189 + 5.4x – (100 – x) = 6.4x + 89 = 217 6.4x = 128 x = 20 Hence, option c) is the correct answer.
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