Question
The ratio of the present ages of P and Q is 6:5
respectively. If the age of P 10 years hence from now will be 100% more than the age of Q 4 years ago from now, then find the age of P 3 years ago from now. TYPE 8Solution
Let the present ages of P and Q be 6x and 5x years respectively. According to the question, => 6x + 10 = 2(5x – 4) => 6x + 10 = 10x - 8 => 4x = 18 => x = 4.5 Required age = 6x – 3 = 24 years
Pipes X, Y, and Z can fill a tank in 12 hours, 6 hours, and 8 hours respectively. If the efficiencies of pipes X and Y are each reduced by 50% of their ...
Time taken by a tap to fill a tank is 8 hours. If the time taken by tap to fill the tank gets doubled due to a leakage in the tank, then find the time t...
If a tank can be filled by a tap in 16 hours, but due to an outlet, it actually takes 4 hours longer to fill the tank, find the duration in which the ou...
Pipes X and Y can independently fill a tank in 80 minutes and 90 minutes respectively, while pipes X and Z together take 3 hours to fill the same tank. ...
Pipe A alone fill the tank in x hours and Pipe B alone fill the tank in (x – 8) hours. If the efficiency of pipe B is triple of pipe A and pipe A fill...
In what time would a cistern be filled by three pipes whose diameter are 2cm, 2*2/3cm, 4cm running together, when the largest pipe alone fill the cister...
Pipe A and B can fill the pool in 36 minutes and 48 minutes, respectively. Pipe C can empty half filled pool in 36 minutes. If all the pipes are opened ...
Tap A can fill tank X in 20 minutes, but with a leakage (tank Y), it takes 33(1/3) minutes to fill. Tap B operates at 20% less efficiency than Tap A. De...
Tap A can fill a tank in 20 hours and tap B can emptied it is 25 hours. Tap A starts filling and they opened for 1 hour each alternatively in what time ...
Three pipes A, B, and C can fill a tank in 15 hours, 20 hours, and 25 hours respectively. All three pipes are opened together, but after 4 hours, pipe C...
