Question
The ages of A, B and C are in the ratio 3:4:5 and the
sum of their ages is 72. Find the ratio of 12 years ago B’s age to C’s age after 12 years.Solution
Let the present age of A, B and C be 3x, 4x and 5x respectively. According to the question, => A + B + C = 72 => 3x + 4x + 5x = 72 => x = 6 B’s age 12 years ago = 4x – 12 = 24 – 12 = 12 C’s age after 12 years = 5x + 12 = 30 + 12 = 42 Required ratio = 12 : 42 = 2:7
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
