Question
The ratio of the present age of A to that of B is 7:9.
Six years ago the ratio of 1/3 of A’s age at that time and 1/3 of B’s age at that time was 1:3. What will be the ratio of A’s age to B’s age 5 years from now?Solution
Let the present age of A and B be 7x and 9x respectively. Now, [(1/3) (7x-6)] / [(1/3) (9x-6)] = 1/3 ⇒ 21x – 18 = 9x – 6 ⇒ 12x = 12 ∴ x = 1 ∴ 5 years from now, A’s age = 7x + 5 = 7 + 5 = 12 years B’s age = 9x + 5 = 14 years ∴ Required ratio = 12/14 = 6:7
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
(24.98)2 = ?2 + (14.99)2
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
9.95% of 1299.99 + 19.95 × 17.05 - 299.99 = ?
6106.11 ÷ √? × 55.9 = 3976.21
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
? % of 759.96 + 932.99 = 1237.01
8.15 of 124.95 ÷ 40.13 + 249.84 X 14.18 - √325 X 149.87 = ? X 10.85
– (8.002)³ + (30.001)² - (4.01)⁴ =?
24.98% of 1682 × (18.2659 ÷ 9.04965)(–4) = ?
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