Question
The ratio of the present age of A to that of B is 7:9.
Six years ago the ratio of 1/3 of Aβs age at that time and 1/3 of Bβs age at that time was 1:3. What will be the ratio of Aβs age to Bβs age 5 years from now?Solution
Let the present age of A and B be 7x and 9x respectively. Now, [(1/3) (7x-6)] / [(1/3) (9x-6)] = 1/3 β 21x β 18 = 9x β 6 β 12x = 12 Β β΄ x = 1 β΄ 5 years from now, Aβs age = 7x + 5 = 7 + 5 = 12 years Bβs age = 9x + 5 = 14 years β΄ Required ratio = 12/14 = 6:7
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