Question
In a certain code language, 'Court of additional
district' is coded as 'bhg rfv ope fgt', 'Judge life District' is coded as 'axf bhg vbn', and 'Life of additional' is coded as 'ope vbn fgt'. What is the code for 'Judge life Court' in this coding language?Solution
'Court of additional district' is coded as 'bhg rfv ope fgt' …… (I) 'Judge life District' is coded as 'axf bhg vbn' ……(II) 'Life of additional' is coded as 'ope vbn fgt' …….(III) From (I) and (II), we will get the code for ‘District' is ‘bhg’ From (I) and (III), we will get the code for ‘of additional’ is ‘'ope fgt' From (I), we will get the code for ‘'Court’ is ‘rfv’ From (II), we will get the code for ‘‘Judge life’ is ‘'axf vbn' So, the code for 'Judge life Court' is ‘axf vbn rfv’
What approximate value will replace the question mark (?) in the following?
24.99...
`[(7.99)^2 - (13.001)^2 + (4.01)^3]^2=` ?
(3/7 of 1049.88 + 44.95% of 799.79) ÷ (√168.89 + 24.77% of 400.11) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
The greatest number that will divide 398,436, and 542 leaving 7, 11, and 15 as remainders, respectively, is:
95.001% of 8219.99 - 4/9 % of 5399.98 + 109.99 = ?Â
25.22% of (59.9 × 8.01) + 69.97 =?Â
9.992 + (5.01 × 4.98) + ? = 225.03
29.88% of 3599.90 + 5/12 of 2399.81 – 34.81% of 1200.18 = ?
15.15% of (150.50 + 249.50) + 8.08³ - (10.10 of 5.05) = ? of (75.75 - 25.25)
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