In ΔABC, PQ is parallel to BC If AP: PB= 3:7 and AQ= 3 cm, AC is equal to?
As in ΔABC, PQ is parallel to BC then ΔAPQ is similiar to ΔABC, So by similarity, AP/AB = AQ/AC So 3/(3 + 7) = 3/AC or 3/10 = 3/AC or AC = 10 cm
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