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Fish caught by “i”: a i (2000- (a i + Σ j≠i a j )). Now we have to maximise this expression. Therefore differentiating w.r.t ai and equating to 0 a i = 1000 - Σ j≠i a j /2 Now each player will try to maximise his catch and assuming each one using the same strategy a i = a * to achieve equilibrium a* = 1000 - (n-1) a* /2 a* = 2000 / (n+1) So catch by each player=[2000 / (n+1)] 2
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