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ATQ; Let the total task be = 48 {LCM(16, 24)} Efficiency of ‘Ankit’ = (48/16) = 3 units/day Efficiency of ‘Bina’ = (48/24) = 2 units/day Task done by ‘Ankit’ in 6 days = 3 × 6 = 18 units Task done by ‘Ankit’ and ‘Bina’ together in 4 days = 5 × 4 = 20 units Remaining task = 48 – 18 – 20 = 10 units Time taken by ‘Bina’ to complete the remaining task = 10/2 = 5 days
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