In the questions given below, there are four statements followed by three conclusions I, II and
III. You have to take the four given statements to be true even if they seem to be at variance from commonly known facts. Read all the conclusions and then decide which of the given conclusions logically follows from the given statements disregarding commonly known facts. If 'X@Y' means 'No Y is X', 'X%Y' means 'Some Y are X', 'X&Y' means 'All X are Y', 'X#Y' means 'Only a few X are Y', 'X?Y' means 'All X can be Y'. 'X+Y' means 'Some X can be Y'.  Statements: Apple @ Orange, Pear & Apple, Orange # Kiwi, Banana @ Kiwi Conclusion:
I. Banana ? Apple
II. Kiwi + Pear
III. Pear % Orange

After decoding the codes, we get, Statements: Apple @ Orange means 'No Orange is Apple'. Pear & Apple means 'All Pear are Apple'. Orange # Kiwi means 'Only a few Orange are Kiwi'. Banana @ Kiwi means 'No Kiwi is Banana'. No Orange is Apple (E) → Conversion → No Apple is Orange (E) + Only a few Orange are Kiwi (I) → Some Kiwi are not Apple (O). No Kiwi is Banana (E) → Conversion → No Banana is Kiwi (E) + Some Kiwi are not Apple (O) → Probable conclusion → All Banana can be Kiwi (A). Hence conclusion I follows. Some Kiwi are not Apple (O) + Some Apple are Pear (I) → Probable conclusion → All Kiwi can be Pear (A). Hence conclusion II follows. No Orange is Apple (E) + Some Apple are Pear (I) → Some Orange are not Pear (O).  Hence conclusion III does not follow.