Question
Statements:Some pastries are cakes. No cake is a
pudding. All puddings are sweets. Conclusions:I. Some sweets are not cakes. II. Some pastries are not puddings. In each of the questions below are given three statements followed by three conclusions numbered I and II. You have to take the given statements to be true even if they seem to be at variance with commonly known facts. Read all the conclusions and then decide which of given conclusions logically follows from the given  statements disregarding commonly known facts. Give answerSolution
No cake is a pudding (E) + All puddings are sweets (A) ⇒ some sweets are not cakes (O*). Hence, conclusion I will follow. Some pastries are cakes (I) + No cake is a pudding (E) ⇒ some pastries are not puddings (O). Hence, conclusion II will also follow. ALTERNATE METHOD: Possible cases: 
In all the cases, I and II both follow.
In these questions, relationship between different elements is shown in the statements. The statements are followed by conclusions.
Statements:...
Statement- 1 - 6#≥9#≥10#≤5#
2 - 7*≤10#˃5*≥6*
Conclusions:
1) 7* > 6*
2) 6* > 7*
3) 6# ≤ 5#<...
In the question, assuming the given statements to be true, find which of the following conclusion(s) among the two conclusions is/are true and then giv...
Statements: P = Q ≥ S > U = Y, U ≤ R < T ≤ W < V
Conclusions:
I. V > Y
II. P ≥ R
III. T < Q
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is/are definitely true and th...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is/are definitely true and then...
In the question, assuming the given statements to be true, find which of the conclusion (s) among given two conclusions is /are definitely true and the...
Statement: D < M < P = V = E ≥ T > Z
Conclusion: I. P > Z II. D > E
In the question, assuming the given statements to be true, find which of the conclusion (s) among given three conclusions is /are definitely true and t...
Statement: B > C = J; B > S > E; B < N
Conclusion: I. E < C      II. J ≤ E
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