Question
A man walks 20 km towards East turns right and walks 25
km, further he turns right and walk 15 km and again walks 10 km after turning right. Finally, he runs 13 km after turning his left. What is the shortest distance between his initial point and final point?Solution
AB = 20 Km towards East, BC = 25 Km, CD = 15 Km, DE = 10 Km, EF = 13 Km. 
Distance between his initial point & final point = (AO)² + (FO)² = AF² (25 - 10)² + (13-5)² = AF² (15)² + (8)² = AF² 225 + 64 = AF² 289 = AF² AF = 17 km.
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