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    Question

    Find the smallest number by which 845 must be multiplied so

    that the product is divisible by 30.
    A 2 Correct Answer Incorrect Answer
    B 6 Correct Answer Incorrect Answer
    C 9 Correct Answer Incorrect Answer
    D 5 Correct Answer Incorrect Answer

    Solution


    ATQ,

    Since, 845 = 5 × 13 × 13

    To be divisible by ‘30’, a number must be divisible by 2, 3, and 5.

    Here, 845 is divisible by 5 only. So, we need to multiply it by both 2 and 3, i.e., 2 × 3 = 6.

    Therefore, required answer is 6.

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