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      Question

      Find the smallest number by which 845 must be multiplied so

      that the product is divisible by 30.
      A 2 Correct Answer Incorrect Answer
      B 6 Correct Answer Incorrect Answer
      C 9 Correct Answer Incorrect Answer
      D 5 Correct Answer Incorrect Answer

      Solution


      ATQ,

      Since, 845 = 5 Γ— 13 Γ— 13

      To be divisible by β€˜30’, a number must be divisible by 2, 3, and 5.

      Here, 845 is divisible by 5 only. So, we need to multiply it by both 2 and 3, i.e., 2 Γ— 3 = 6.

      Therefore, required answer is 6.

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