Question
In a 300-metre race, ‘Aman’ beats ‘Bhanu’ and
‘Charu’ by 30 metres and 60 metres, respectively. If ‘Bhanu’ and ‘Charu’ ran a 180 metre race, then ‘Bhanu’ will beat ‘Charu’ by:Solution
ATQ,
Distance covered by ‘Bhanu’ in the time taken by ‘Aman’ to cover 300 metres = 300 – 30 = 270 meters
Distance covered by ‘Charu’ in the time taken by ‘Aman’ to cover 300 metres = 300 – 60 = 240 meters
Since, the time taken is same in this case, the ratio of speeds of ‘Bhanu’ and
‘Charu’ will be same as the ratio of distances.
Ratio of speeds of ‘Bhanu’ and ‘Charu’ = 270 : 240 = 9 : 8
So, in a 180-metre race, ‘Bhanu’ will beat ‘Charu’ by
180 – (180 × 8/9) = 180 – 160 = 20 metres
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Statements: C % K, K @ L, L & U, U $ G
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...Statements: J ≥ Q, L > S, L ≥ Q, K = J < N
Conclusion:
I. L > J
II. N > Q
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Conclusions : I. Q @ S ...
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Statements: C > D ≥ E > F; H ≥ G < F; I > H
Conclusions:
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III. C ≤ HStatements: R = S > Y ≥ T = W ≥ U > V > X
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I. Y < X
II. S > V
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