Question
Combination of ages of which pair is maximum?
Study the following information carefully and answer the questions given below it. Seven person namely –A, B, D, M, N, J and K was born in different years with the current base is taken as 2018. None of them was born before 1950 and not after 2004. Each person likes different colours viz. PINK, WHITE, Black, Orange, YELLOW, CREAM and Blue. If it is mentioned that a person’s age is considered as the last two digits of another person’s birth year, then it will be at any sequence. For example, if the age of ‘P’ is considered as last two digits of birth year of ‘Q’ which is 1975; then the age of ‘P’ might be either 75 or 57 years. Age of D is 46 years and likes Blue. A’s age is equal to the last two digit of birth year of K. The difference of age of D and N is 12 years. B’s age is equal to the last two digit of birth year of N. J likes Orange. The difference of age of one who likes Orange and A is 28 years. One who likes white was born after 1972. B likes PINK. J and M were not born on adjacent years. Difference of age of one who likes Black and one who likes PINK is 16 years. The difference of age of K and B is 6 years. Age of A is not less than 54 years. One who was born in 1978 likes yellow.
Again, we have: The difference of age of K and B is 6 years, that means we have four possible birth year for K, in case (1a) K was born in 1964, in case (1b) K was born in 1976, in case (2a) K was born in 1952, in case (2b) K was born in 1964. A’s age is equal to the last two digit of birth year of K, that means in case (1a)& case (2b) possible age of A is either 64 or 46 years, as D was born in 1972 thus A must born in 1954, in case (1b) possible age of A is either 67 or 76 years, as no person was born before 1950 thus A must born in 1951, in case (2a) possible age of A is either 52 or 25 years, as A was not born after 1965, that means case (2a) is not valid. Based on above given information we have: 
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