Question
The sum of the exponents of the prime factors in the
prime factorization of 540 isSolution
ATQ, Let’s break 540 into prime factors: 540 = 2 × 2 × 3 × 3 × 3 × 5 So, 540 = 2² × 3³ × 5¹ Then, add the exponents: The exponent of 2 is 2. The exponent of 3 is 3. The exponent of 5 is 1. Total = 2 + 3 + 1 = 6. Hence, 6 is the answer.
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