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    Question

    When the digits, which are odd in the number

    ‘43289567’ are decreased by 2 and the remaining digits are increased by 1, then what is the product of 5th digit from the right end and 2nd digit from the left end of the new number arranged?
    A 12 Correct Answer Incorrect Answer
    B 9 Correct Answer Incorrect Answer
    C 10 Correct Answer Incorrect Answer
    D 15 Correct Answer Incorrect Answer

    Solution

    4            3            2            8            9            5            6            7 5            1             3            9             7            3            7            5 5th digit from the right – 9 2nd digit from the left – 1 Product = 9 x 1 = 9

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