Question
150 litres of Mixture βAβ (water + alcohol) contains
32% water and remaining alcohol while 112 litres of mixture βBβ (milk + water) contains 20 litres more milk than water. Find the sum of quantities of water in both the given mixtures.Solution
Quantity of water in mixture βAβ = 150 Γ 0.32 = 48 litres Let the quantity of water in mixture βBβ = βxβ litres Then, quantity of milk in mixture βBβ = (x + 20) litres So, x + (x + 20) = 112 Or, 2x + 20 = 112 Or, x = (112 β 20) Γ· 2 Or, x = 46 Therefore, quantity of water in mixture βBβ = x = 46 litres So, sum of quantity of water in both the mixtures = 48 + 46 = 94 litres.
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