Question
In a mixture consisting of 400 ml of wine and lemon, the
volume of wine exceeds that of the lemon by (200/3)%. Following the removal and replacement of 20% of the mixture with lemon, this procedure is repeated once more. Calculate the final quantity of wine in the mixture.Solution
Let, the quantity of Lemon in the initial mixture be '3x' ml. So, the quantity of wine in the initial mixture = (5/3) × 3x = '5x' ml So, 5x + 3x = 400 Or, 8x = 400 Or, x = (400/8) So, x = 50 So, the quantity of wine in the initial mixture = 5x = 5 × 50 = 250 ml ATQ, Quantity of wine in the final mixture = 250 × 0.8 × 0.8 = 160 ml
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