New RBI Grade B 2025 Notification will come Soon! Enroll Here

    Question

    In a mixture consisting of 400 ml of wine and lemon, the

    volume of wine exceeds that of the lemon by (200/3)%. Following the removal and replacement of 20% of the mixture with lemon, this procedure is repeated once more. Calculate the final quantity of wine in the mixture.
    A 200 ml Correct Answer Incorrect Answer
    B 165 ml Correct Answer Incorrect Answer
    C 160 ml Correct Answer Incorrect Answer
    D 175 ml Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    Let, the quantity of Lemon in the initial mixture be '3x' ml. So, the quantity of wine in the initial mixture = (5/3) × 3x = '5x' ml So, 5x + 3x = 400 Or, 8x = 400 Or, x = (400/8) So, x = 50 So, the quantity of wine in the initial mixture = 5x = 5 × 50 = 250 ml ATQ, Quantity of wine in the final mixture = 250 × 0.8 × 0.8 = 160 ml

    Practice Next