Start learning 50% faster. Sign in now
The number of persons is attending a seminar after A is the same as the number of persons is attending the seminar before C. A attends seminar two months after B, who attends the seminar on an odd date. C and J attend the seminar in the same month. We will have four cases: If B attends seminar on 5th January, then A will attend on 5th April. C will attend on 8 September and J will attend on 5th September. If B attends seminar on 5th April, then A will attend on 5th July. C will attend on 8 July but we do not have dates for J. If B attends seminar on 5th July, then A will attend on 5th September. C will attend on 8 April and J will attend on 5th April. If B attends seminar on 5th September, then A will attend on 5th December. C will attend on 8 January and J will attend on 5th January. The number of persons is attending the seminar between J and B is the same as the number of persons is attending the seminar between A and I. In case 1, there are five person between B and J. So, I attends seminar on 5th December. In case 3, there is one person between B and J. So, I attends seminar on 5th December. In case 4, there are five person between B and J. So, I attends seminar on 5th April. F attends seminar three months before I, who attends seminar in one of the months has 31 days. Case 1 and 4 will get discarded as we know that I attends the seminar in December and F should have attended in September. In case 3, F attends seminar on 8 September.
At least two persons attend the seminar between E and A. So, E attends seminar on 8 December. G attends seminar on the 8th of the month but not in January. Now it is clear that G attends the seminar on 8 July. The number of persons attending the seminar between F and C is one less than the number of persons is attending the seminar between H and G . H and D attend seminars in the same month. We know that three person are there between F and C. It means that there would have been four person between G and H. So, H and D attend seminar on 5th January and 8 January respectively. Final arrangement as shown below:
119 ÷ [22 - {90 ÷ (23 - 105 ÷ (7 × 3))}] = ?
[{(3 × 54 × 21)/63} + 6] / 6 = √?
(342 – 20% of 5280) = ? ÷ 3
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Simplify the given expression.
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
Evaluate: (768÷16)×(125÷25)−(81÷9)×12
22 – 15 + 20 × 18 ÷ 6 – 34 = ?
350% of (450 / 1.5) = ?% of 4200
Simplify the expression:
(4x² - 16) / (2x - 4)