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Maximum ten boxes are placed one above the other. There are four boxes between Box E and Box B, which at the topmost position. Two boxes are placed between Box E and Box C. One box is placed between Box C and Box D, which has 12 balls. One box is placed between Box F and Box D. Inferences: From above statements, Given, maximum 10 boxes are placed one above the other. Let the position of the box in lowermost is numbered as 1 and topmost is 10 (note: We start with 10 boxes, if necessary it can be changed with respect to given statements) Given, Box B is at topmost position. Then, Box E is fifth to below Box B (4 boxes between them) Box C is placed either 3rd to above Box E or 3rd to below Box E (2 boxes between them). Thus we get two possibilities. Case-1: Here, Box C is placed 3rd to above Box E. Then, Box D (12 balls) is placed 2nd to below Box C (1 box is between them). Box F is 2nd to below Box D (1 box is between them, only possibility) Case-2: Here, Box C is placed 3rd to below Box E. Then, Box D (12 balls) is placed 2nd to above Box C (1 box is between them, only possibility). Box F is 2nd to above Box D (1 box is between them, only possibility) By using above information, we get the following table as shown
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-3 -10 -40 -185 -905 -4500
-4 a b c d e
Find the value of d.
...640 322 164 86 48 ?
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21, 63, 315, ?, 19845, 218295
If 7 16 x 90 171 292
Then, 2x 2 + 1 + x ...
40 30 20 ? 7.5 4.375
12, 18, 28, 42, 52, ?
462 478 510 558 ?
...9 4.5 4.5 9 36 ?