Question
In the number '76589648', '1' is subtracted from all the
digits. In the new number thus formed, from the left end we first arrange all the odd digits in ascending order and then all the even digits in ascending order, then what is the sum of the digit which is 3rd from the left end and the digit which is 3rd from the right end after rearrangement?Solution
7Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8 6Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 7 3Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 8 Required sum = 5 + 4 = 9.
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