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    Question

    When the digits, which are odd in the number

    ‘4586353485’ are decreased by 2 and the remaining digits are increased by 1, then what is the sum of 4th digit from the left end and 5th digit from the right end of the rearranged number?
    A 8 Correct Answer Incorrect Answer
    B 6 Correct Answer Incorrect Answer
    C 9 Correct Answer Incorrect Answer
    D 10 Correct Answer Incorrect Answer
    E None of the above Correct Answer Incorrect Answer

    Solution

    4          5          8          6          3          5          3          4          8          5 5          3          9          7          1         3          1          5          9          3 Required sum = 7 + 3 = 10

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