Question
When the digits, which are odd in the number
‘4586353485’ are decreased by 2 and the remaining digits are increased by 1, then what is the sum of 4th digit from the left end and 5th digit from the right end of the rearranged number?Solution
4Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 6Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 4Â Â Â Â Â Â Â Â Â 8Â Â Â Â Â Â Â Â Â 5 5Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 7Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â 3Â Â Â Â Â Â Â Â Â 1Â Â Â Â Â Â Â Â Â 5Â Â Â Â Â Â Â Â Â 9Â Â Â Â Â Â Â Â Â 3 Required sum = 7 + 3 = 10
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