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3 9 8 4 5 2 5 7 8 3 1 7 9 5 3 3 3 5 9 1 9 9 7 5 5 3 3 3 1 1 Sum of digits of first half from the left end = 9 + 9 + 7 + 5 + 5 = 35. Sum of digits of second half from the right end = 3 + 3 + 3 + 1 + 1 = 11. Require difference = 35 – 11 = 24.
Statement: T > B = P ≥ C ; B ≥ J > F; O≤ J ≤ C