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Start learning 50% faster. Sign in nowSTEP I: M sits third to the left of O who sits an immediate neighbour of S. Three persons sit between Q and S who sits second to the left of N. As per these statements, we can say that there are three possible cases and the arrangement will look like this:
STEP II: R sits to the immediate left of P who sits second to the left of M. Both R and Q sit adjacent to each other. The number of persons sits between P and S is one less than the number of persons sits between S and R when counted from the right of both P and S respectively. At least one person sits between N and R when counted from the right of N. As per these statements, CASE I and CASE III get eliminated and we continue with CASE II and the final arrangement will look like this:
I. x2 - 17x + 70 = 0
II. y2 - 11y + 28 = 0
I. 3x6- 19x3+16=0
II. 9y4- 27y2+20=0
I). p2 - 26p + 165 = 0
II). q2 + 8q - 153 = 0
I). 5p2 - p - 4 = 0
II). q2 - 12q + 27 = 0
I. 5x + 2y = 31
II. 3x + 7y = 36
I. 8x² - 74x + 165 = 0
II. 15y² - 38y + 24 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
I. 2 x² - 15 + 18 = 0
II. x²- 3 + 2 = 0
...Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 24x + 143 = 0
Equation 2: y² - 26y + 165 = 0