If L sits second to the left of O then how many seats are between L and R when counted from the right of R?
STEP I: M sits third to the left of O who sits an immediate neighbour of S. Three persons sit between Q and S who sits second to the left of N. As per these statements, we can say that there are three possible cases and the arrangement will look like this: STEP II: R sits to the immediate left of P who sits second to the left of M. Both R and Q sit adjacent to each other. The number of persons sits between P and S is one less than the number of persons sits between S and R when counted from the right of both P and S respectively. At least one person sits between N and R when counted from the right of N. As per these statements, CASE I and CASE III get eliminated and we continue with CASE II and the final arrangement will look like this:
I. x2 – 7x + 12 = 0
II. y2 – 7y + 10 = 0
I. 12y2 + 11y – 15 = 0
II. 8x2 – 6x – 5 = 0
I. 3y2+ 16y + 16 = 0
II. 2x2+ 19x + 45 = 0
I. x2 – 18x + 81 = 0
II. y2 – 3y - 28 = 0
I. 2x2– 5x – 63 = 0
II. 2y2– 7y – 72 = 0
I. 5x² = 19x – 12
II. 5y² + 11y = 12
I.12a2– 55a + 63 = 0
II. 8b2- 50b + 77 = 0
...I. 66x² - 49x + 9 = 0
II. 46y² - 37y - 30 = 0
I. 15y2+ 4y – 4 = 0
II. 15x2+ x – 6 = 0
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0