Question
All the letters provided below are arranged in English
alphabetical order from left to right. Then in each combination, the first letter from the left end is numbered as I, the second letter from the left end is numbered as II, and so on. Hence in each combination, I, II, III, IV, and V will denote the position of the letters from the left end. [i] RQWZJ [ii] CAEJM [iii] FPDBE [iv] FDLZX From each of the given words, the letters, which are at the same positions are clubbed together. The letters which are at position [I] will form a word if taken in order of combination [i], [ii], [iii], and [iv] respectively and similarly form [I II III IV and V]. Then, how many meaningful words will be formed?Solution
Arranging the letter in English alphabetical order, we get: [i] RQWZJ - JQRWZ [ii] CAEJM β ACEJM [iii] FPDBE β BDEFP [iv] FDLZX β DFLXZ On clubbing together in (I, II, III, IV, and V) from the left end, we get: Only III will make a meaningful word i.e. βREELβ.
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